• @[email protected]
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            92 years ago

            It’s a little more complicated than that. You have to be summing everyone who is still tied to all the previous tracks. It needs to be a geometric sum formula.

            • @[email protected]
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              112 years ago

              You could just move them over whenever someone decides to double it up. That way the person that was going to die alone is doomed to die anyway. 😂

              • @[email protected]
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                42 years ago

                I wonder if we do stack it till every human is tied to the track whos at the lever?

                Does the train/AI decide?

                • @[email protected]
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                  32 years ago

                  The current version of GPT is willing to sacrifice billions of robots for humanities sake. However, it proposed to strap alien civilizations to the track next. And in that case it would choose to save the larger group…

            • Sabazius
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              2 years ago

              It’ll just be one fewer junctions. 2^n is always one more than the sum of 21+…2(n-1)

              • @[email protected]
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                12 years ago

                I think you have to include 2^0 for that to be true?

                e.g 2^0 = 1, 2^1 = 2 2^0 + 2^1 = 1 + 2 = 3, 2^2 = 4 … 7, 8 15,16 31, 32 etc.

    • @[email protected]
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      02 years ago

      A later choice of nobody on each track would be ideal. Even a psycho at the switch would be unable to kill.